Added solution to problem 6

sumSquareDifference/main.c

@@ -0,0 +1,7 @@
+#include <stdio.h>
+
+int func();
+
+int main() {
+	printf("%d\n",func());
+}

sumSquareDifference/main.s

@@ -2,13 +2,42 @@
 .section .text
 
 func:   @ Find the difference between the sum of the squares and the square of the sum, for the first hundred numbers.
-@ (a^2+b^2) = a^2 + b^2 + 2ab
+@ (a+b)^2 = a^2 + b^2 + 2ab
-@ Therefore, the difference must be 2ab
+@ (a+b+c)^2 = a^2 + b^2 + c^2 + 2(ab +bc + ca)
-
+@ Therefore, the difference must be 2(ab + ac + ad .... + bc + bd + be ... + cd + ce .....)
-
+
-
+MOV R0,#0
+MOV R2,#1   @ 'a' from the equation above
+MOV R3,#2   @ 'b' from the equation above
+
+mainloop:
+MUL R1,R2,R3  @ 'a' * 'b' - keep in mind we need to do this for all possible 2-number permutations in the sequence
+ADD R0,R0,R1  @Add the result to R0, which will be returned
+
+incr_b:
+ADD R3,R3,#1  @ Increments 'b'
+
+chk_b:
+CMP R3,#100   @ If 'b' is less than or equal to 100, we continue the multiplication
+BLE mainloop
+
+incr_a:
+ADD R2,R2,#1  @ Increments 'a'
+
+new_b:  @This is a way for me to store R2+1 into R3
+ADD R2,R2,#1
+MOV R3,R2
+SUB R2,R2,#1
+
+chk_a:
+CMP R2,#100
+BLT mainloop
 
 
+mul2:
+LSL R0,R0,#1   @Bitwise left shit by 1 - Multiplies by 2
 
+return:
+BX LR
 
 .section .data