Added function and examples for ReplaceAllFunc()
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@@ -2,6 +2,7 @@ package regex_test
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import (
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"fmt"
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"strings"
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"gitea.twomorecents.org/Rockingcool/kleingrep/regex"
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)
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@@ -167,6 +168,14 @@ func ExampleReg_ReplaceAllLiteral() {
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regexStr := `fox|dog`
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inputStr := "the quick brown fox jumped over the lazy dog"
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regexComp := regex.MustCompile(regexStr)
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fmt.Println(regexComp.ReplaceAll(inputStr, `duck`))
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fmt.Println(regexComp.ReplaceAllLiteral(inputStr, `duck`))
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// Output: the quick brown duck jumped over the lazy duck
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}
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func ExampleReg_ReplaceAllFunc() {
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regexStr := `\w{5,}`
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inputStr := `all five or more letter words in this string are capitalized`
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regexComp := regex.MustCompile(regexStr)
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fmt.Println(regexComp.ReplaceAllFunc(inputStr, strings.ToUpper))
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// Output: all five or more LETTER WORDS in this STRING are CAPITALIZED
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}
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@@ -428,6 +428,7 @@ func (re Reg) ReplaceAllLiteral(src string, repl string) string {
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if currentMatch < len(zerogroups) && i == zerogroups[currentMatch].StartIdx {
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dst += repl
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i = zerogroups[currentMatch].EndIdx
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currentMatch += 1
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} else {
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dst += string(src[i])
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i++
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@@ -435,3 +436,25 @@ func (re Reg) ReplaceAllLiteral(src string, repl string) string {
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}
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return dst
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}
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// ReplaceAllFunc replaces every match of the expression in src, with the return value of the function replFunc.
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// replFunc takes in the matched string. The return value is substituted in directly without expasion.
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func (re Reg) ReplaceAllFunc(src string, replFunc func(string) string) string {
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zerogroups := re.FindAll(src)
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currentMatch := 0
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i := 0
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dst := ""
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for i < len(src) {
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if currentMatch < len(zerogroups) && i == zerogroups[currentMatch].StartIdx {
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dst += replFunc(src[zerogroups[currentMatch].StartIdx:zerogroups[currentMatch].EndIdx])
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i = zerogroups[currentMatch].EndIdx
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currentMatch += 1
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} else {
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dst += string(src[i])
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i++
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}
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}
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return dst
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}
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