Wrote function and example for ReplaceAllLiteral()

regex/example_test.go

@@ -162,3 +162,11 @@ func ExampleReg_ReplaceAll() {
 	fmt.Println(regexComp.ReplaceAll(inputStr, `$2$1`))
 	// Output: d5t9
 }
+
+func ExampleReg_ReplaceAllLiteral() {
+	regexStr := `fox|dog`
+	inputStr := "the quick brown fox jumped over the lazy dog"
+	regexComp := regex.MustCompile(regexStr)
+	fmt.Println(regexComp.ReplaceAll(inputStr, `duck`))
+	// Output: the quick brown duck jumped over the lazy duck
+}

regex/matching.go

@@ -404,7 +404,7 @@ func (re Reg) ReplaceAll(src string, repl string) string {
 	currentMatch := 0
 	dst := ""
 	for i < len(src) {
-		if currentMatch <= len(matches) && matches[currentMatch][0].IsValid() && i == matches[currentMatch][0].StartIdx {
+		if currentMatch < len(matches) && matches[currentMatch][0].IsValid() && i == matches[currentMatch][0].StartIdx {
 			dst += re.Expand("", repl, src, matches[currentMatch])
 			i = matches[currentMatch][0].EndIdx
 			currentMatch++
@@ -415,3 +415,23 @@ func (re Reg) ReplaceAll(src string, repl string) string {
 	}
 	return dst
 }
+
+// ReplaceAllLiteral replaces all matches of the expression in src, with the text in repl. The text is replaced directly,
+// without any expansion.
+func (re Reg) ReplaceAllLiteral(src string, repl string) string {
+	zerogroups := re.FindAll(src)
+	currentMatch := 0
+	i := 0
+	dst := ""
+
+	for i < len(src) {
+		if currentMatch < len(zerogroups) && i == zerogroups[currentMatch].StartIdx {
+			dst += repl
+			i = zerogroups[currentMatch].EndIdx
+		} else {
+			dst += string(src[i])
+			i++
+		}
+	}
+	return dst
+}