Proof of concept for leftmostLongest function

master
Aadhavan Srinivasan 1 week ago
parent 8e07a5ed0e
commit ade48bd64e

@ -0,0 +1,5 @@
leftmostLongest :: (Foldable t) => [t a] -> t a
leftmostLongest xs =
let lastElem = (last xs)
filteredLst = (filter (\val -> (length val) == (length lastElem)) xs)
in head filteredLst
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